CHAPTER 1 : Real Numbers
Revision Checklist
- Introduction
- Euclid's Division Lemma
- Theorem 1.1 : Euclid's Division Lemma
Given positive integers a and b, there exists unique integers q and r satisfying
a = bq + r, 0 ≤ r ≤ b.
- Definitions:
Algorithm : An algorithm is a series of well defined steps which gives a procedure for solving a
type of problem.
Lemma : A lemma is a proven statement used for proving another statement.
- Euclid's Division Algorithm
- Step 1.
Apply Euclid's division lemma, to c and d. So, we find whole numbers, q and
r such that c = dq + r, 0 ≤ r < d.
- Step 2.
If r = 0, d is the HCF of c and d. If r ≠ 0, apply the
division lemma to d and r.
- Step 3.
Continue the process till the remainder is zero. The divisor at this stage will be the required HCF.
- Exercise 1.1
- The Fundamental Theorem of Arithmetic
- Theorem 1.2 : Fundamental Theorem of Arithmetic
Every composite number can be expressed (factorised) as a product of primes, and this factorisation is unique,
apart from the order in which the prime factors occur.
OR
The prime factorisation of a natural number is unique, except for the order of its factors.
- For any two positive integers a and b,
HCF (a, b) × LCM (a, b) = a × b.
- Exercise 1.2
- Revisiting Irrational Numbers
- Revisiting Rational Numbers and Their Decimal Expansions
- Theorem 1.5 : Let x be a rational number whose decimal expansion terminates. Then x can be expressed
in the form p⁄q, where p and q are coprime, and the prime factorisation of q is
of the form 2n5m, where n, m are non-negative integers.
- Theorem 1.6 : Let x = p⁄q be a rational number, such that the prime factorisation of q
is of the form 2n5m, where n, m are non-negative integers. Then
x has a decimal expansion which terminates.
- Theorem 1.7 : Let x = p⁄q be a rational number, such that the prime factorisation of q
is not of the form 2n5m, where n, m are non-negative integers. Then
x has a decimal expansion which is non-terminating repeating (recurring).
- The decimal expansion of every rational number is either terminating or non-terminating repeating
- Exercise 1.4